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Topic review - Polynomial / in GF(2^8)?
Author Message
wienand
  Post subject:   Reply with quote
Dear Xijin Tang,

the polynomial x-y is no unit in the ring GF(2^8)[x,y]. So Singular does not allow you to divide by it.

It would allow you to divide a by any number in the coefficient field, i.e. a polynomial only in z.

Sincerely,

Oliver Wienand
Post Posted: Tue Sep 20, 2005 4:46 pm
Xijin Tang
  Post subject:  Polynomial / in GF(2^8)?  Reply with quote
> ring r=(2^8,z),(x,y),lp;
> poly a=z^45*(x2-y2);
> poly b=x-y;
> a/b;
? not implemented
? error occurred in STDIN line 4: `a/b;`
Does this means I could not use / in GF(2^8),
will you implement that function in future?
Thank you very much!

email: tangxij@mails.gscas.ac.cn
Posted in old Singular Forum on: 2005-05-27 04:23:16+02
Post Posted: Thu Aug 11, 2005 5:33 pm


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