Back to Forum | View unanswered posts | View active topics





Post a reply
Username:
Note:If not registered, provide any username. For more comfort, register here.
Subject:
Message body:
Enter your message here, it may contain no more than 60000 characters. 

Smilies
:D :) :( :o :shock: :? 8) :lol: :x :P :oops: :cry: :evil: :twisted: :roll: :wink: :!: :?: :idea: :arrow: :| :mrgreen:
Font size:
Font colour
Options:
BBCode is ON
[img] is ON
[flash] is OFF
[url] is ON
Smilies are ON
Disable BBCode
Disable smilies
Do not automatically parse URLs
Confirmation of post
To prevent automated posts the board requires you to enter a confirmation code. The code is displayed in the image you should see below. If you are visually impaired or cannot otherwise read this code please contact the %sBoard Administrator%s.
Confirmation code:
Enter the code exactly as it appears. All letters are case insensitive, there is no zero.
   

Topic review - ring delaration
Author Message
malex
  Post subject:  Re: ring delaration  Reply with quote
Hi,

you can try using
Code:
list L = ringlist(r);
and change the field component (L[1]) with it coming from a ring with appropriate field. Afterwards create a new ring out of it, e.g. with
Code:
def NEW = ring(L); setring NEW;


Cheers,
Oleksandr
Post Posted: Tue Dec 04, 2012 9:36 pm
lkastner
  Post subject:  ring delaration  Reply with quote
I have a ring called r and want to create a copy of this ring, but with a different characteristic. Is there some working alternative to
Code:
int newchar = 5;
ring r = newchar,(varstr(r)),dp;

?

Thanks,
Lars
Post Posted: Mon Dec 03, 2012 11:54 pm


It is currently Fri May 13, 2022 11:02 am
Powered by phpBB © 2000, 2002, 2005, 2007 phpBB Group