Post a reply
Username:
Note:If not registered, provide any username. For more comfort, register here.
Subject:
Message body:
Enter your message here, it may contain no more than 60000 characters. 

Smilies
:D :) :( :o :shock: :? 8) :lol: :x :P :oops: :cry: :evil: :twisted: :roll: :wink: :!: :?: :idea: :arrow: :| :mrgreen:
Font size:
Font colour
Options:
BBCode is ON
[img] is ON
[flash] is OFF
[url] is ON
Smilies are ON
Disable BBCode
Disable smilies
Do not automatically parse URLs
Confirmation of post
To prevent automated posts the board requires you to enter a confirmation code. The code is displayed in the image you should see below. If you are visually impaired or cannot otherwise read this code please contact the %sBoard Administrator%s.
Confirmation code:
Enter the code exactly as it appears. All letters are case insensitive, there is no zero.
   

Topic review - monomial's coefficient
Author Message
  Post subject:  Re: monomial's coefficient  Reply with quote
Another possibility is 'coeffs'
(http://www.singular.uni-kl.de/Manual/4-0-3/sing_271.htm)
and a third one:
Code:
jet(f/x^3,0)
Post Posted: Tue May 24, 2016 4:29 pm
  Post subject:  Re: monomial's coefficient  Reply with quote
There is 'coeffs' command for this.
ring r = 0,(x,y,z),dp;
poly f = 2 x ^ 3 + 5z^3;
> coeffs(f,x);
_[1,1]=-5z3 //coefficient of x^0
_[2,1]=0 // coeff of x^1
_[3,1]=0 // coeff of x^2
_[4,1]=2 // coeff of x^3

If you need to extract a specific entry from this matrix, directly specify the position,
> coeffs(f,x)[4,1]; //For x^3
2

Similarly for other ring variables. It shouldn't be too difficult to convert it into a function.
Post Posted: Tue May 24, 2016 7:49 am
  Post subject:  monomial's coefficient  Reply with quote
friends,
I'm looking for a singular procedure to return a given monomial's coefficient
of a polynomial.

Example poly f = 2 x ^ 3 + 5z^3;
test (f, x ^ 3) // --> 2
test (f, y ^ 3) // --> 0
who can help me?
Post Posted: Mon May 23, 2016 9:36 pm


It is currently Fri May 13, 2022 10:56 am
cron
Powered by phpBB © 2000, 2002, 2005, 2007 phpBB Group