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Topic review - monomial's coefficient |
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Re: monomial's coefficient |
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Posted: Tue May 24, 2016 4:29 pm |
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Re: monomial's coefficient |
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There is 'coeffs' command for this. ring r = 0,(x,y,z),dp; poly f = 2 x ^ 3 + 5z^3; > coeffs(f,x); _[1,1]=-5z3 //coefficient of x^0 _[2,1]=0 // coeff of x^1 _[3,1]=0 // coeff of x^2 _[4,1]=2 // coeff of x^3
If you need to extract a specific entry from this matrix, directly specify the position, > coeffs(f,x)[4,1]; //For x^3 2
Similarly for other ring variables. It shouldn't be too difficult to convert it into a function.
There is 'coeffs' command for this. ring r = 0,(x,y,z),dp; poly f = 2 x ^ 3 + 5z^3; > coeffs(f,x); _[1,1]=-5z3 //coefficient of x^0 _[2,1]=0 // coeff of x^1 _[3,1]=0 // coeff of x^2 _[4,1]=2 // coeff of x^3
If you need to extract a specific entry from this matrix, directly specify the position, > coeffs(f,x)[4,1]; //For x^3 2
Similarly for other ring variables. It shouldn't be too difficult to convert it into a function.
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Posted: Tue May 24, 2016 7:49 am |
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monomial's coefficient |
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friends, I'm looking for a singular procedure to return a given monomial's coefficient of a polynomial.
Example poly f = 2 x ^ 3 + 5z^3; test (f, x ^ 3) // --> 2 test (f, y ^ 3) // --> 0 who can help me?
friends, I'm looking for a singular procedure to return a given monomial's coefficient of a polynomial.
Example poly f = 2 x ^ 3 + 5z^3; test (f, x ^ 3) // --> 2 test (f, y ^ 3) // --> 0 who can help me?
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Posted: Mon May 23, 2016 9:36 pm |
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It is currently Fri May 13, 2022 10:56 am
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