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Post subject: power representation of the finite field coefficients Posted: Wed Aug 11, 2010 7:04 pm |
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It seems currently that if the coefficient ring is a finite field, a coefficient element is printed as polynomial of the generator of the coefficient ring. Assuming the generator is a primitive element, is it possible to make coefficients are printed always as a power of the primitive element? This feature saves a lot of space when printing polynomials over finite fields. If this feature is not in Singular, I want to submit a feature request for this. If it is already in Singular, let me know how to turn it on.
Thank you in advance.
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hannes
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Post subject: Re: power representation of the finite field coefficients Posted: Wed Aug 11, 2010 7:29 pm |
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Joined: Wed May 25, 2005 4:16 pm Posts: 275
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That depends on the declaration: ring r=(8,a),x,dp; creates a representation in powers of, while ring r=(2,a),x,dp; minpoly=a3-a+1; creates an isomorphic ring with polynomials in a as coefficients.
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