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| unspecified minpoly https://www.singular.uni-kl.de/forum/viewtopic.php?f=10&t=2488 |
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| Author: | shengyushen [ Fri Feb 06, 2015 11:11 am ] |
| Post subject: | unspecified minpoly |
Dear all: I am learning using singular , and I run the following script in singular > ring A1=(2^3,a),x,dp; > minpoly ; 1*a^3+1*a^1+1*a^0 > ring A2=(2,a),x,dp; // ** redefining A2 ** > minpoly ; 0 I am confused by it, I have not specified a monopoly for both A1 and A2 rings, but the A1 have a monopoly already, but not the A2. Does this means that the A1 have only 1 monopoly so we don't need to specify it? Shengyu Shen |
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| Author: | pankajsejwal [ Mon May 30, 2016 8:28 am ] |
| Post subject: | Re: unspecified minpoly |
ring r1 = (2^3,a),x,dp; is generated by a3+a+1 working as maximal ideal and it is a known fact and also stored in Singular CAS, https://github.com/Singular/Sources/tre ... y/gftables |
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