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monomial's coefficient https://www.singular.uni-kl.de/forum/viewtopic.php?f=10&t=2530 |
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Author: | gstic [ Mon May 23, 2016 9:36 pm ] |
Post subject: | monomial's coefficient |
friends, I'm looking for a singular procedure to return a given monomial's coefficient of a polynomial. Example poly f = 2 x ^ 3 + 5z^3; test (f, x ^ 3) // --> 2 test (f, y ^ 3) // --> 0 who can help me? |
Author: | pankajsejwal [ Tue May 24, 2016 7:49 am ] |
Post subject: | Re: monomial's coefficient |
There is 'coeffs' command for this. ring r = 0,(x,y,z),dp; poly f = 2 x ^ 3 + 5z^3; > coeffs(f,x); _[1,1]=-5z3 //coefficient of x^0 _[2,1]=0 // coeff of x^1 _[3,1]=0 // coeff of x^2 _[4,1]=2 // coeff of x^3 If you need to extract a specific entry from this matrix, directly specify the position, > coeffs(f,x)[4,1]; //For x^3 2 Similarly for other ring variables. It shouldn't be too difficult to convert it into a function. |
Author: | hannes [ Tue May 24, 2016 4:29 pm ] |
Post subject: | Re: monomial's coefficient |
Another possibility is 'coeffs' (http://www.singular.uni-kl.de/Manual/4-0-3/sing_271.htm) and a third one: Code: jet(f/x^3,0)
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