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shengyushen
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Post subject: unspecified minpoly Posted: Fri Feb 06, 2015 11:11 am |
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Joined: Tue Feb 03, 2015 3:09 pm Posts: 1
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Dear all:
I am learning using singular , and I run the following script in singular > ring A1=(2^3,a),x,dp; > minpoly ; 1*a^3+1*a^1+1*a^0 > ring A2=(2,a),x,dp; // ** redefining A2 ** > minpoly ; 0
I am confused by it, I have not specified a monopoly for both A1 and A2 rings, but the A1 have a monopoly already, but not the A2.
Does this means that the A1 have only 1 monopoly so we don't need to specify it?
Shengyu Shen
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pankajsejwal
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Post subject: Re: unspecified minpoly Posted: Mon May 30, 2016 8:28 am |
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Joined: Sat Apr 16, 2016 7:25 pm Posts: 8
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