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 Post subject: turning an ideal into a ring: division
PostPosted: Sat Mar 14, 2009 5:36 am 

Joined: Sat Mar 14, 2009 3:08 am
Posts: 1
Let I = < i_n > be an ideal which is contained in a proper ideal J = < j_n > of some (commutative) polynomial ring R.

J is a ring without a unit. I is an ideal of the ring J as well. Just as one can meaningfully divide polynomials in R with respect to one of its ideals (using Groebner Bases), can one divide polynomials in the ring J with respect to its ideal I?

In other words, is there, given a polynomial p in J, a notion of q = p (mod I) within the ring J? By this I mean

p = Sum(k) alpha_k * i_k + q

where all the alpha_k are polynomials in J.

If yes, can Singular compute the alpha's and q?


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PostPosted: Sun Mar 29, 2009 5:14 pm 

Joined: Mon Aug 29, 2005 9:22 am
Posts: 41
Location: Kaiserslautern, Germany
I do not quite understand the question. What do you impose on q?

In any case, the expression Sum(k) alpha_k * i_k is in I*J and you could
apply the Singular command division(p,I*J);

The result can then be used to get an expression as you propose,
with q the usual remainder of the division by I*J. Is this what you mean?


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